Chemistry / Chem 2130 · Atom · ~20 seconds
ΔG° Relates to K
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At equilibrium, ΔG equals zero and Q equals K, reducing the nonstandard free energy expression to ΔG° = −RT ln K, linking standard free energy change directly to K.
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A large negative ΔG° corresponds to a large K, an equilibrium mixture favoring products heavily.
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This equation uses K itself, not Q — substituting a nonequilibrium Q gives a meaningless result.